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anonymous

  • 5 years ago

does this integral converge or diverge integral 3 to -3 y/sqrt 9-y^2. i found the integral ut having trouble with rest of problem

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  1. anonymous
    • 5 years ago
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    What did the integral turn out to be?

  2. anonymous
    • 5 years ago
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    -\[-\sqrt{9-y^2}\]

  3. anonymous
    • 5 years ago
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    Have you tried splitting up your limits of integration? Integral from 3 to 0 + integral from 0 to -3 should equal the integral from 3 to -3.

  4. anonymous
    • 5 years ago
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    yah

  5. anonymous
    • 5 years ago
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    the answer should be zero but i am get -6

  6. anonymous
    • 5 years ago
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    what variable are you integrating over? because if you're integrating with respect to y, it's -6. but with respect to x, it is 0.

  7. anonymous
    • 5 years ago
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    i used u subsitution to find the integral and plugged in what i subsituted for it , so with rerespect to y. there is no x in this integral

  8. anonymous
    • 5 years ago
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    hey do you know where my mistake may be

  9. anonymous
    • 5 years ago
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    were you saying that the solved integral was \[-\sqrt(9-y^2)\] ? Or that function was the integrand of the question? I might be reading the question wrong.

  10. anonymous
    • 5 years ago
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    what you just typed is what i got for my integral

  11. anonymous
    • 5 years ago
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    alright then. so you just have to take the limit of this function as it approaches infinity to determine whether or not it converges or diverges. The limit of this function to infinity is 0 (assuming that we are not dealing with imaginary numbers) because the function only exists between -3 and 3. There is no real component that makes the solution nonzero, which is why it would be zero. What is the original function that you have to integrate?

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