does this integral converge or diverge integral 3 to -3 y/sqrt 9-y^2. i found the integral ut having trouble with rest of problem

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- anonymous

What did the integral turn out to be?

- anonymous

-\[-\sqrt{9-y^2}\]

- anonymous

Have you tried splitting up your limits of integration?
Integral from 3 to 0 + integral from 0 to -3 should equal the integral from 3 to -3.

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- anonymous

yah

- anonymous

the answer should be zero but i am get -6

- anonymous

what variable are you integrating over? because if you're integrating with respect to y, it's -6. but with respect to x, it is 0.

- anonymous

i used u subsitution to find the integral and plugged in what i subsituted for it , so with rerespect to y. there is no x in this integral

- anonymous

hey do you know where my mistake may be

- anonymous

were you saying that the solved integral was \[-\sqrt(9-y^2)\] ? Or that function was the integrand of the question? I might be reading the question wrong.

- anonymous

what you just typed is what i got for my integral

- anonymous

alright then. so you just have to take the limit of this function as it approaches infinity to determine whether or not it converges or diverges. The limit of this function to infinity is 0 (assuming that we are not dealing with imaginary numbers) because the function only exists between -3 and 3. There is no real component that makes the solution nonzero, which is why it would be zero.
What is the original function that you have to integrate?

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