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y = log x
If y = 10, then what is x?

(-8x+3)/5=y

y=-8/5x +3/5

any questions on what I did so far?

can you show me how you got that?

your equation was
8x+5y=3
right?

right

I was equation of y in terms of x

wait is this the answer to my question?

So I subtracted 8x from both side
I got
5y=-8x+3

any questions so far djm?

so this isnt the answer to my question?

don't quite understand your statement of equation of y in terms of x

does this help?

ya that is a little better

so getting back to our equation
5y=-8x+3

ok

we want y by itself so we divide by 5 BOTH SIDES.

ok

y=-8/5x+3/5

any questions so far?

no good so far

Now we have to go back to the original question

ok sorry had to refresh again

i need help please T_T no one wants to help

"perpendicular to the given line" is the keyword from your question

okay

PLEASE PLEASE! IM SORRY! BUT I NEED HELP,T___T

parallel lines have same slope
perpendicular lines have negative reciprocal slope

right

going back to our equation
y=-8/5x+3/5

so noes going to help me!

>:( fine, feel my wrath of rage

y-5=5/8(x-0)
that is your equation
any question