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anonymous

  • 5 years ago

square root of 8 over 8x^2

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  1. anonymous
    • 5 years ago
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    \[\sqrt(8/8x^2)\]

  2. anonymous
    • 5 years ago
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    is this right?

  3. anonymous
    • 5 years ago
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    no \[\sqrt{8}\div 8x ^{2}\]

  4. anonymous
    • 5 years ago
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    okay thanks

  5. anonymous
    • 5 years ago
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    sqrt(8) can be written as sqrt(4)* sqrt(2)

  6. anonymous
    • 5 years ago
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    wait what i just want to know how to simplify it. i have teh answer in the book i just need help with the work. thats not the answer.

  7. anonymous
    • 5 years ago
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    sqrt(4) =2 so 2sqrt(2)/8x^2 sqrt(2)/4x^2

  8. anonymous
    • 5 years ago
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    my book says the answer should be 2sqrt(3)/3

  9. anonymous
    • 5 years ago
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    are you sure you're looking at the right problem? because you're not gonna be able to get rid of the x^2 on the bottom

  10. anonymous
    • 5 years ago
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    oh god your right. SORRY!! is sqrt(8)/ sqrt(6)

  11. anonymous
    • 5 years ago
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    okay for that you do the same thing as above. break the 8 up into 4 * 2 and break the 6 up into 3 * 2 . now you have :\[{\sqrt{4}\sqrt{2}} \over \sqrt{2}\sqrt{3}\] now just divide the sqrt(2) out

  12. anonymous
    • 5 years ago
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    \[{2 \over \sqrt{3}} \times {\sqrt{3} \over \sqrt{3}}\]

  13. anonymous
    • 5 years ago
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    this will get rid of your radical on the bottom and change it to 3

  14. anonymous
    • 5 years ago
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    okay i think i get it. your doing a different way then what im used to but it makes sense

  15. anonymous
    • 5 years ago
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    how do you normally do it?

  16. anonymous
    • 5 years ago
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    heres and example our teacher would break sqrt(8) to the sqrt(2x2x2) and sqrt(6) to sqrt(2x3)

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