anonymous
  • anonymous
square root of 8 over 8x^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\sqrt(8/8x^2)\]
anonymous
  • anonymous
is this right?
anonymous
  • anonymous
no \[\sqrt{8}\div 8x ^{2}\]

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anonymous
  • anonymous
okay thanks
anonymous
  • anonymous
sqrt(8) can be written as sqrt(4)* sqrt(2)
anonymous
  • anonymous
wait what i just want to know how to simplify it. i have teh answer in the book i just need help with the work. thats not the answer.
anonymous
  • anonymous
sqrt(4) =2 so 2sqrt(2)/8x^2 sqrt(2)/4x^2
anonymous
  • anonymous
my book says the answer should be 2sqrt(3)/3
anonymous
  • anonymous
are you sure you're looking at the right problem? because you're not gonna be able to get rid of the x^2 on the bottom
anonymous
  • anonymous
oh god your right. SORRY!! is sqrt(8)/ sqrt(6)
anonymous
  • anonymous
okay for that you do the same thing as above. break the 8 up into 4 * 2 and break the 6 up into 3 * 2 . now you have :\[{\sqrt{4}\sqrt{2}} \over \sqrt{2}\sqrt{3}\] now just divide the sqrt(2) out
anonymous
  • anonymous
\[{2 \over \sqrt{3}} \times {\sqrt{3} \over \sqrt{3}}\]
anonymous
  • anonymous
this will get rid of your radical on the bottom and change it to 3
anonymous
  • anonymous
okay i think i get it. your doing a different way then what im used to but it makes sense
anonymous
  • anonymous
how do you normally do it?
anonymous
  • anonymous
heres and example our teacher would break sqrt(8) to the sqrt(2x2x2) and sqrt(6) to sqrt(2x3)

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