square root of 8 over 8x^2

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square root of 8 over 8x^2

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[\sqrt(8/8x^2)\]
is this right?
no \[\sqrt{8}\div 8x ^{2}\]

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okay thanks
sqrt(8) can be written as sqrt(4)* sqrt(2)
wait what i just want to know how to simplify it. i have teh answer in the book i just need help with the work. thats not the answer.
sqrt(4) =2 so 2sqrt(2)/8x^2 sqrt(2)/4x^2
my book says the answer should be 2sqrt(3)/3
are you sure you're looking at the right problem? because you're not gonna be able to get rid of the x^2 on the bottom
oh god your right. SORRY!! is sqrt(8)/ sqrt(6)
okay for that you do the same thing as above. break the 8 up into 4 * 2 and break the 6 up into 3 * 2 . now you have :\[{\sqrt{4}\sqrt{2}} \over \sqrt{2}\sqrt{3}\] now just divide the sqrt(2) out
\[{2 \over \sqrt{3}} \times {\sqrt{3} \over \sqrt{3}}\]
this will get rid of your radical on the bottom and change it to 3
okay i think i get it. your doing a different way then what im used to but it makes sense
how do you normally do it?
heres and example our teacher would break sqrt(8) to the sqrt(2x2x2) and sqrt(6) to sqrt(2x3)

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