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anonymous

  • 5 years ago

Physics problem: A vector with 20 degrees is scaled to 10cm and is added to a vector with 80 degrees scaled to 15cm. When graphing them with a protractor, then adding them to find the resultant, what would the approx. equilibrant resultant be?

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  1. anonymous
    • 5 years ago
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    Did you get started and got stuck?

  2. anonymous
    • 5 years ago
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    My peer solved the problem and got a resultant of 22.8 cm while I got ~17 cm.

  3. anonymous
    • 5 years ago
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    I missed the day of the lab so I'm presuming that I did something wrong.

  4. anonymous
    • 5 years ago
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    when adding vector you add x component to x component and y with y

  5. anonymous
    • 5 years ago
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    So do you know how to find component of the vector

  6. anonymous
    • 5 years ago
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    ?

  7. anonymous
    • 5 years ago
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    Would the component of the vectors with 10cm and 15 cm be [\tan^{-1} (15/10)\]

  8. anonymous
    • 5 years ago
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    20 degree 10 cm assuming 20 degree from positive x direction... x component- 10 cos(20) y component -10 sin(20) Now do that to second vector then add them togther

  9. anonymous
    • 5 years ago
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    On it right now. :)

  10. anonymous
    • 5 years ago
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    Okay. Got it.

  11. anonymous
    • 5 years ago
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    good

  12. anonymous
    • 5 years ago
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    most of the time(NOT ALL THE TIME) x is cos() and y is sin()

  13. anonymous
    • 5 years ago
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    Cool. For the some totals, I got 12 for x and 18.2 for y.

  14. anonymous
    • 5 years ago
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    sum*

  15. anonymous
    • 5 years ago
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    Okay so my answer is 21.8 which is 1 cm off from my peer.

  16. anonymous
    • 5 years ago
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    Yet, when I draw it with a protractor and measure the resultant it comes out a bit odd.

  17. anonymous
    • 5 years ago
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    math is more accurate than measuring

  18. anonymous
    • 5 years ago
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    lol It should seem so.

  19. anonymous
    • 5 years ago
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    Thank you for your help. I'll figure the rest out.

  20. anonymous
    • 5 years ago
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    you still here?

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