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Physics problem: A vector with 20 degrees is scaled to 10cm and is added to a vector with 80 degrees scaled to 15cm. When graphing them with a protractor, then adding them to find the resultant, what would the approx. equilibrant resultant be?

Mathematics
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Did you get started and got stuck?
My peer solved the problem and got a resultant of 22.8 cm while I got ~17 cm.
I missed the day of the lab so I'm presuming that I did something wrong.

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Other answers:

when adding vector you add x component to x component and y with y
So do you know how to find component of the vector
?
Would the component of the vectors with 10cm and 15 cm be [\tan^{-1} (15/10)\]
20 degree 10 cm assuming 20 degree from positive x direction... x component- 10 cos(20) y component -10 sin(20) Now do that to second vector then add them togther
On it right now. :)
Okay. Got it.
good
most of the time(NOT ALL THE TIME) x is cos() and y is sin()
Cool. For the some totals, I got 12 for x and 18.2 for y.
sum*
Okay so my answer is 21.8 which is 1 cm off from my peer.
Yet, when I draw it with a protractor and measure the resultant it comes out a bit odd.
math is more accurate than measuring
lol It should seem so.
Thank you for your help. I'll figure the rest out.
you still here?

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