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anonymous
 5 years ago
ok this one is simple looking to figure out if the answer would be negative or positive Y
6  13y ≤ 4  12y
6 13y +12y ≤ 4  12y + 12y
6  y ≤ 4
6  6  y ≤ 4  6
y ≤ 2
anonymous
 5 years ago
ok this one is simple looking to figure out if the answer would be negative or positive Y 6  13y ≤ 4  12y 6 13y +12y ≤ 4  12y + 12y 6  y ≤ 4 6  6  y ≤ 4  6 y ≤ 2

This Question is Closed

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0i would do this in another way..

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0instead of adding 12y to both sides, add 13 y to both sides

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.02 ≤ y or y is more than or equal to two

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0Please click on become a fan if I helped, I really want to get to 100!! Thanks =)

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0sorry meant to the next level lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well what lost me was line 3 as it should read 6(y) shouldnt it ?

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0okay let me try this step by step

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.06  13y ≤ 4  12y 6 13y +13y ≤ 4  12y + 13y 6 ≤ 4 + y 6  4 ≤ y 2 ≤ y y \[\ge\] 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so the entire problem was backwords i thought normal operations was to put the variable to the left with numbers on the right ok thanks i think lol

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0lol sorry, im pretty bad at y>x i am never sure if its y<x or anything.. i just try it backwards lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0raj, you did the problem right. the last step is y >= 2. when you multiply or divide by 1 in an inequality, you have to switch the direction of the inequality.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thank you its making a little mo anymore its been a few to many years lol been out of school for to long

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you are ever in doubt of whether you have the correct answer, you can test it by plugging in an xvalue and see if the answer you got makes sense. since we got x>2, you could plug in x = 3 to the inequality and see if it is true.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry got booted off one system had to log the other in

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you for your help
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