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anonymous
 5 years ago
SR (600y^23)
anonymous
 5 years ago
SR (600y^23)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{600y ^{23}}\] is the actual equation

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0\[(600y^{23})^{1/2}\] = \[10 (y^{22/2})\sqrt{6*y} \]

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0\[10y^{11}\sqrt{68y}\]

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0woops sorry: \[10y^{11}\sqrt{6*y}\]

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0Please click on become a fan if I helped, I really want to get to the next level!! Thanks =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah I am still lost as can be...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your in alegebra 2 right? im might be in the same chapter as you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0essentially it is algebra 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay soo first see in you can find a sqrt of 600.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it comes out as a decimal so I know that I have to simplify first and to me it would make the most sense to have it be \[\sqrt{100}\sqrt{6}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0being as 100 is a perfect square

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what my teacher taught me was to write it like Sqrt(100x6) then break those down to more simple numbers. Sqrt(50x2x2x3) [50x2=100] and 2x3=6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you guys want to go through the problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am going throught the problem...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the sqrt will eventually look like this (5x5x2x2x2x3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you have 2 5's and 2 2's. take both and multiple 5 and 2 and put their product on the outside of the squareroot.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your equation should look like this. 10sqrt(6y^23) [6=product of remianing numbers in root]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for just figure out how many times 2 can go into 23 any remaing numbers remain in the root. answer = \[10y^{11}\sqrt{6y}\]
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