A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

SR (600y^23)

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\sqrt{600y ^{23}}\] is the actual equation

  2. bahrom7893
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[(600y^{23})^{1/2}\] = \[10 (y^{22/2})\sqrt{6*y} \]

  3. bahrom7893
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[10y^{11}\sqrt{68y}\]

  4. bahrom7893
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    woops sorry: \[10y^{11}\sqrt{6*y}\]

  5. bahrom7893
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Please click on become a fan if I helped, I really want to get to the next level!! Thanks =)

  6. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    any questions?

  7. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah I am still lost as can be...

  8. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    your in alegebra 2 right? im might be in the same chapter as you.

  9. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    essentially it is algebra 2

  10. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay soo first see in you can find a sqrt of 600.

  11. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it comes out as a decimal so I know that I have to simplify first and to me it would make the most sense to have it be \[\sqrt{100}\sqrt{6}\]

  12. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    being as 100 is a perfect square

  13. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what my teacher taught me was to write it like Sqrt(100x6) then break those down to more simple numbers. Sqrt(50x2x2x3) [50x2=100] and 2x3=6

  14. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Do you guys want to go through the problem

  15. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ?

  16. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i am going throught the problem...

  17. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the sqrt will eventually look like this (5x5x2x2x2x3)

  18. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you have 2 5's and 2 2's. take both and multiple 5 and 2 and put their product on the outside of the squareroot.

  19. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    your equation should look like this. 10sqrt(6y^23) [6=product of remianing numbers in root]

  20. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for just figure out how many times 2 can go into 23 any remaing numbers remain in the root. answer = \[10y^{11}\sqrt{6y}\]

  21. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.