anonymous
  • anonymous
Need help with the washer method: x=1-y^2, x=2+y^2, =-1, y=1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
*should be y=-1
anonymous
  • anonymous
x=-1 , y=-1?
anonymous
  • anonymous
try out this website. http://tutorial.math.lamar.edu/Classes/CalcII/CalcII.aspx

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anonymous
  • anonymous
So you have two function. Find out which one is to the right.
anonymous
  • anonymous
x=2+y^2 would be to the right, right?
anonymous
  • anonymous
hold on
anonymous
  • anonymous
are your functions correct, they don't seem to intersect
anonymous
  • anonymous
yep, they are correct. I also forgot to put its revolved around the y-axis
anonymous
  • anonymous
because the functions don't even touch each other
anonymous
  • anonymous
That's really strange, I wonder if the text made an error
anonymous
  • anonymous
For washer method, we are supposed to take revolution of intersection between two functions
anonymous
  • anonymous
That much I understand, maybe I should try converting the equation to xs and see what happens.
anonymous
  • anonymous
If we change second function to x=-2+y^2 we can solve it, do you wanna
anonymous
  • anonymous
sure : )
anonymous
  • anonymous
We will rotate around x=-3
anonymous
  • anonymous
Here come the integral \[\pi \int\limits_{?}^{?}((-y^2-1)-(y^2-2)+1)^2-1\]
anonymous
  • anonymous
dy
anonymous
  • anonymous
did you get it, mathrocks?
anonymous
  • anonymous
Ok, this is starting to make some sense.
anonymous
  • anonymous
you have to find points of intersection though
anonymous
  • anonymous
Never memorize any formula for disc,shell, washer method
anonymous
  • anonymous
I can find the intersection points with no problem. It's just setting up the washer equation that sometimes trips me up. Thanks for your help, I appreciate it.
anonymous
  • anonymous
just know that when you are doing this type of problem, you are adding up circle
anonymous
  • anonymous
If I helped you in somehow, can you fan me
anonymous
  • anonymous
I'll remember that and will practice drawing the actual graphs. And the fan request has been done. : )

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