- anonymous

Need help with the washer method:
x=1-y^2, x=2+y^2, =-1, y=1

- chestercat

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- anonymous

*should be y=-1

- anonymous

x=-1 , y=-1?

- anonymous

try out this website. http://tutorial.math.lamar.edu/Classes/CalcII/CalcII.aspx

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## More answers

- anonymous

So you have two function. Find out which one is to the right.

- anonymous

x=2+y^2 would be to the right, right?

- anonymous

hold on

- anonymous

are your functions correct, they don't seem to intersect

- anonymous

yep, they are correct. I also forgot to put its revolved around the y-axis

- anonymous

because the functions don't even touch each other

- anonymous

That's really strange, I wonder if the text made an error

- anonymous

For washer method, we are supposed to take revolution of intersection between two functions

- anonymous

That much I understand, maybe I should try converting the equation to xs and see what happens.

- anonymous

If we change second function to
x=-2+y^2
we can solve it, do you wanna

- anonymous

sure : )

- anonymous

We will rotate around x=-3

- anonymous

Here come the integral
\[\pi \int\limits_{?}^{?}((-y^2-1)-(y^2-2)+1)^2-1\]

- anonymous

dy

- anonymous

did you get it, mathrocks?

- anonymous

Ok, this is starting to make some sense.

- anonymous

you have to find points of intersection though

- anonymous

Never memorize any formula for disc,shell, washer method

- anonymous

I can find the intersection points with no problem. It's just setting up the washer equation that sometimes trips me up. Thanks for your help, I appreciate it.

- anonymous

just know that when you are doing this type of problem, you are adding up circle

- anonymous

If I helped you in somehow, can you fan me

- anonymous

I'll remember that and will practice drawing the actual graphs.
And the fan request has been done. : )

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