anonymous
  • anonymous
f(x) = -3x^2-4x+5 f(0) & f(2) Help! I am seriously LOST!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
hey, how's it going?
anonymous
  • anonymous
its not lol I am so lost on this it is not even funny!
anonymous
  • anonymous
what is exactly is the question asking?

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anonymous
  • anonymous
i have no idea I am given what is typed above with the statement at the begining of the assignment that say simplify or solve...
anonymous
  • anonymous
so does it seem like they want you to find what f(0) and f(2) are?
anonymous
  • anonymous
that would be my guess
anonymous
  • anonymous
are you familiar with what a function is?
anonymous
  • anonymous
i probably would be but this is my first math class in almost 9 years
anonymous
  • anonymous
basically a function is a machine that you feed an x-value, and it spits out a y-value
anonymous
  • anonymous
so whatever number you put into the function machine, it does what it does and you get some output
anonymous
  • anonymous
anyways, it is asking you to feed 0 and 2 into the function and see what comes out. so you need to plug those values in for x and compute the result
anonymous
  • anonymous
so instead of it saying -3x^2 I should put the 0 where that x is so it would read (3)(0)^2 ???
anonymous
  • anonymous
right, to find f(0), put a 0 wherever you see an x and keep everything else the same
anonymous
  • anonymous
so my answers would be 5 and 33?
anonymous
  • anonymous
5 looks right, but how did you get 33?
anonymous
  • anonymous
\[(-3(2))^{2} -4(2) +5\]
anonymous
  • anonymous
are those outer parentheses in the first part in the original equation, or did you add them?
anonymous
  • anonymous
I added them
anonymous
  • anonymous
with a question like this you need to make sure to just plug in the number to the exact equation and not change it in any way. do you see why the extra parentheses make a difference?
anonymous
  • anonymous
i have to go in a second, but the -3 shouldn't be squared, the exponent only applies to x

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