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anonymous

  • 5 years ago

I haveone more question. If the lenght of twolegs of a right triangle are: the square root of 3 and the square root of 6 , then the length of the hypotenuse is: ?

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  1. anonymous
    • 5 years ago
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    Have you seen the equation: a^2+b^2=c^2?

  2. anonymous
    • 5 years ago
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    yes

  3. anonymous
    • 5 years ago
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    Do you know what a and b represent?

  4. anonymous
    • 5 years ago
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    is this the legs

  5. anonymous
    • 5 years ago
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    Yep! So then the c represents the hypotenuse. So do you think you would know how to set up the problem?

  6. anonymous
    • 5 years ago
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    not with square roots I don't

  7. anonymous
    • 5 years ago
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    Well, the square roots (surprisingly) actually makes things a little easier. So we start with our original formula: a^2+b^2=c^2 And since you said a and b are the legs, we can substitute the measurements you gave: \[(\sqrt(3))^2+(\sqrt(6))^2=c^2\]

  8. anonymous
    • 5 years ago
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    So technically if you square a square root it sort of cancels with one another. So \[(\sqrt(3))^2=3\]

  9. anonymous
    • 5 years ago
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    and the same idea for \[(\sqrt(6))^2\] which would equal 6.

  10. anonymous
    • 5 years ago
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    So where would you go from there?

  11. anonymous
    • 5 years ago
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    would I go 3+6=c which would be c=9

  12. anonymous
    • 5 years ago
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    Well technically it would be 3+6=9, so 9=c^2. So then you would take the sqaure root of both sides so you have c=?

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