## anonymous 5 years ago I haveone more question. If the lenght of twolegs of a right triangle are: the square root of 3 and the square root of 6 , then the length of the hypotenuse is: ?

1. anonymous

Have you seen the equation: a^2+b^2=c^2?

2. anonymous

yes

3. anonymous

Do you know what a and b represent?

4. anonymous

is this the legs

5. anonymous

Yep! So then the c represents the hypotenuse. So do you think you would know how to set up the problem?

6. anonymous

not with square roots I don't

7. anonymous

Well, the square roots (surprisingly) actually makes things a little easier. So we start with our original formula: a^2+b^2=c^2 And since you said a and b are the legs, we can substitute the measurements you gave: $(\sqrt(3))^2+(\sqrt(6))^2=c^2$

8. anonymous

So technically if you square a square root it sort of cancels with one another. So $(\sqrt(3))^2=3$

9. anonymous

and the same idea for $(\sqrt(6))^2$ which would equal 6.

10. anonymous

So where would you go from there?

11. anonymous

would I go 3+6=c which would be c=9

12. anonymous

Well technically it would be 3+6=9, so 9=c^2. So then you would take the sqaure root of both sides so you have c=?