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If u is t+1 and du is 1dt then what is the integral (u-1)u*u^(-1/2)?

Mathematics
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hey, how's it going?
?
Having issues with integral calculus and am way behind. I have to get caught up soon since the final is in two weeks. Basically I will probably be up until my girlfriend tells me to come to bed.

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Other answers:

subtle brag about girlfriend?
no just truth...
I'm not that shallow.
haha, just kidding, do you mean the integral of ((u-1)(u)(u^(-1/2)))?
yeah its via u-substitution. The original was kinda vague about where to start but I finally got past that with help from somebody here. dwobinkle or something like that
so do you understand the part that has been done so far, or do you want to go over that?
well if you like I can show you the original problem. I do get what has already been done because it was just the concept of trying factoring before anything else
well from this point, you can simplify what you have by multiplying it out
have you tried that?
you can show me the original problem if you want just to make sure that the part you are showing me is correct
Yeah but I am sadly failing at my algebra
u(u-1) = u^2 - u
so then you have (u^2 - u)(u^(-1/2))
you still there?
yeah just brushed my teeth...computer being weird online
so do you follow so far? can you take it from here?
...
I got that far but I'm not quite sure...is it just regular power integrations now?
got how far
well the u^-1/2 should be multiplied into the parenthetical shouldn't it? Then we can just integrate?
yes, sounds right, so what did you get as your answer?
well that part leads to the integral of ((u^2/u^(1/2))-(u/u^(1/2))
can you keep going?
would the first term come out something like (2u^3/3u^1/2)?
are you trying to integrate it straight from the last thing you typed?
try using google chrome, that seems to be working better for me on this site
Okay will do...Gonna go to bed thanks for the help.

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