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anonymous

  • 5 years ago

If u is t+1 and du is 1dt then what is the integral (u-1)u*u^(-1/2)?

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  1. anonymous
    • 5 years ago
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    hey, how's it going?

  2. anonymous
    • 5 years ago
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    ?

  3. anonymous
    • 5 years ago
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    Having issues with integral calculus and am way behind. I have to get caught up soon since the final is in two weeks. Basically I will probably be up until my girlfriend tells me to come to bed.

  4. anonymous
    • 5 years ago
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    subtle brag about girlfriend?

  5. anonymous
    • 5 years ago
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    no just truth...

  6. anonymous
    • 5 years ago
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    I'm not that shallow.

  7. anonymous
    • 5 years ago
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    haha, just kidding, do you mean the integral of ((u-1)(u)(u^(-1/2)))?

  8. anonymous
    • 5 years ago
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    yeah its via u-substitution. The original was kinda vague about where to start but I finally got past that with help from somebody here. dwobinkle or something like that

  9. anonymous
    • 5 years ago
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    so do you understand the part that has been done so far, or do you want to go over that?

  10. anonymous
    • 5 years ago
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    well if you like I can show you the original problem. I do get what has already been done because it was just the concept of trying factoring before anything else

  11. anonymous
    • 5 years ago
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    well from this point, you can simplify what you have by multiplying it out

  12. anonymous
    • 5 years ago
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    have you tried that?

  13. anonymous
    • 5 years ago
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    you can show me the original problem if you want just to make sure that the part you are showing me is correct

  14. anonymous
    • 5 years ago
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    Yeah but I am sadly failing at my algebra

  15. anonymous
    • 5 years ago
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    u(u-1) = u^2 - u

  16. anonymous
    • 5 years ago
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    so then you have (u^2 - u)(u^(-1/2))

  17. anonymous
    • 5 years ago
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    you still there?

  18. anonymous
    • 5 years ago
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    yeah just brushed my teeth...computer being weird online

  19. anonymous
    • 5 years ago
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    so do you follow so far? can you take it from here?

  20. anonymous
    • 5 years ago
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    ...

  21. anonymous
    • 5 years ago
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    I got that far but I'm not quite sure...is it just regular power integrations now?

  22. anonymous
    • 5 years ago
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    got how far

  23. anonymous
    • 5 years ago
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    well the u^-1/2 should be multiplied into the parenthetical shouldn't it? Then we can just integrate?

  24. anonymous
    • 5 years ago
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    yes, sounds right, so what did you get as your answer?

  25. anonymous
    • 5 years ago
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    well that part leads to the integral of ((u^2/u^(1/2))-(u/u^(1/2))

  26. anonymous
    • 5 years ago
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    can you keep going?

  27. anonymous
    • 5 years ago
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    would the first term come out something like (2u^3/3u^1/2)?

  28. anonymous
    • 5 years ago
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    are you trying to integrate it straight from the last thing you typed?

  29. anonymous
    • 5 years ago
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    try using google chrome, that seems to be working better for me on this site

  30. anonymous
    • 5 years ago
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    Okay will do...Gonna go to bed thanks for the help.

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