anonymous
  • anonymous
If u is t+1 and du is 1dt then what is the integral (u-1)u*u^(-1/2)?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
hey, how's it going?
anonymous
  • anonymous
?
anonymous
  • anonymous
Having issues with integral calculus and am way behind. I have to get caught up soon since the final is in two weeks. Basically I will probably be up until my girlfriend tells me to come to bed.

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anonymous
  • anonymous
subtle brag about girlfriend?
anonymous
  • anonymous
no just truth...
anonymous
  • anonymous
I'm not that shallow.
anonymous
  • anonymous
haha, just kidding, do you mean the integral of ((u-1)(u)(u^(-1/2)))?
anonymous
  • anonymous
yeah its via u-substitution. The original was kinda vague about where to start but I finally got past that with help from somebody here. dwobinkle or something like that
anonymous
  • anonymous
so do you understand the part that has been done so far, or do you want to go over that?
anonymous
  • anonymous
well if you like I can show you the original problem. I do get what has already been done because it was just the concept of trying factoring before anything else
anonymous
  • anonymous
well from this point, you can simplify what you have by multiplying it out
anonymous
  • anonymous
have you tried that?
anonymous
  • anonymous
you can show me the original problem if you want just to make sure that the part you are showing me is correct
anonymous
  • anonymous
Yeah but I am sadly failing at my algebra
anonymous
  • anonymous
u(u-1) = u^2 - u
anonymous
  • anonymous
so then you have (u^2 - u)(u^(-1/2))
anonymous
  • anonymous
you still there?
anonymous
  • anonymous
yeah just brushed my teeth...computer being weird online
anonymous
  • anonymous
so do you follow so far? can you take it from here?
anonymous
  • anonymous
...
anonymous
  • anonymous
I got that far but I'm not quite sure...is it just regular power integrations now?
anonymous
  • anonymous
got how far
anonymous
  • anonymous
well the u^-1/2 should be multiplied into the parenthetical shouldn't it? Then we can just integrate?
anonymous
  • anonymous
yes, sounds right, so what did you get as your answer?
anonymous
  • anonymous
well that part leads to the integral of ((u^2/u^(1/2))-(u/u^(1/2))
anonymous
  • anonymous
can you keep going?
anonymous
  • anonymous
would the first term come out something like (2u^3/3u^1/2)?
anonymous
  • anonymous
are you trying to integrate it straight from the last thing you typed?
anonymous
  • anonymous
try using google chrome, that seems to be working better for me on this site
anonymous
  • anonymous
Okay will do...Gonna go to bed thanks for the help.

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