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anonymous
 5 years ago
have to integrate (1/.2s+10)ds They get 5ln(.2s+10)5ln10. Having limits of 0 and S. How did they get that?
anonymous
 5 years ago
have to integrate (1/.2s+10)ds They get 5ln(.2s+10)5ln10. Having limits of 0 and S. How did they get that?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{s}(1/.2)s +10)ds\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(.2s+10)=u du=.2 ds ds=1/.2=5 \[5\int\limits_{0}^{s}1/u du\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0 correction ds=1/.2 du=5du
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