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anonymous
 5 years ago
How would you solve the intigral from 1 to 2 for the equation (x/(x^2+1))dx?
anonymous
 5 years ago
How would you solve the intigral from 1 to 2 for the equation (x/(x^2+1))dx?

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bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0let u =x^2 +1 du = 2xdx rewrite the integral as: 1/2 Integral (2xdx/(x^2+1))

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.01/2 Integral (du/u) = 1/2 Lnu = 1/2 Ln(x^2+1) + C

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0Note you dont need abs value any more because x^2 is always positive and positive plus one is still positive!

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0Please click on become a fan if I helped, I really want to get to the next level!! Thanks =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait... is the anser 1/2ln5/2 or 1/2ln3?

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0oh sorry forgot to evaluate: 1/2 Ln(x^2+1) from 1 to 2: (1/2){Ln(2+1)  Ln(1+1)} = (1/2) {Ln3  Ln2} = (1/2)Ln(3/2)

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.02^2 is 4, not 2... (1/2){Ln(4+1)  Ln(1+1)} = (1/2) {Ln5  Ln2} = (1/2)Ln(5/2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep ok that helps alot ty
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