## anonymous 5 years ago Calculate the area between the region described by polar coordinates: 0 ≤ r ≤ sinθ 0 ≤ θ ≤ π

I think it is $\pi/4$

2. anonymous

hey, how's it going?

3. anonymous

Pretty good. I just tried working it out and got pi/2. What I did was: $\int\limits_{0}^{\pi}\sin ^{2}\theta d \theta =$ $1/2(x-\sin \theta \cos \theta)$ from pi to 0 Plugged pi and 0 into it and got pi/2

I think this is the way of proceeding, we get pi/4 $\int\limits_{0}^{\pi} \int\limits_{0}^{\sin \phi}\rho d \rho d \phi$