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how do you solve reciprocal trigonometric functions

Mathematics
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give an example
sec of 0 degrees, 30degrees, 45 degrees, 60 degrees , 90 degrees , 180 degrees, 270 degrees, 360 degrees
sec A= 1/cos A sec 0 = 1/1=1 sec 30 = 1/(sqrt(3)/2)=2/sqrt(3) sec 45 = 1/(1/sqrt 2)=sqrt(2) sec 60 = 1/(1/2)=2 sec 90 = 1/0 = infinity sec 180 = -1 sec 270 = inf sec 360 = 1 discontinuity at 90 and 270 sec 90- = +infinity sec 90+ = -infinity sec 270- = -infinity sec 270+ = +infinity

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