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anonymous

  • 5 years ago

h(t)=(t^4-1)^3) (t^3+1)^4 the chain rule. help please.

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  1. anonymous
    • 5 years ago
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    I will just do the first term 1) When you are taking chain rule always takes derivative of outside function first

  2. anonymous
    • 5 years ago
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    h(t)=(t^4-1)^3 (t^3+1)^4

  3. anonymous
    • 5 years ago
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    2) derivative of outside function is 3(t^4-1)^2 derivative of inside function is 4t^3 multiply inside and outside derivative

  4. anonymous
    • 5 years ago
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    This is a chain rule problem and a product rule. So be careful.. if you don't get it reply.

  5. anonymous
    • 5 years ago
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    I don't get it haha.

  6. anonymous
    • 5 years ago
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    Yes I know but he just wanted help with chain rule so I used the first term as example

  7. anonymous
    • 5 years ago
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    i'm actually a she. Since it is a product rule how would i find in the outside and inside function?

  8. anonymous
    • 5 years ago
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    You will have to use both product rule and chain rule to solve whole problem. The product rule is = F(x)'g(x)+g(x)'(F(x)

  9. anonymous
    • 5 years ago
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    In your function you have two things mutliplied together.

  10. anonymous
    • 5 years ago
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    okay, let me try and figure it out. thanks

  11. anonymous
    • 5 years ago
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    How is going there?

  12. anonymous
    • 5 years ago
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    okay, so i got the derivative of the first one, which was the same as you got. and i ended up with a long equation.

  13. anonymous
    • 5 years ago
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    Yes it's pretty messy if you don't simplify it. i can tell you the answer if you think you got it or you're stumped

  14. anonymous
    • 5 years ago
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    please do

  15. anonymous
    • 5 years ago
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    Here how I would solve it

  16. anonymous
    • 5 years ago
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    applying product rule (t^4-1)^3)* 4(t^3+1)^3 * 3t^2 + (t^3+1)^4 *3(t^4-1)^2 *4t^3 From here it is just algebra

  17. anonymous
    • 5 years ago
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    If It is not a word problem, you can leave it here

  18. anonymous
    • 5 years ago
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    im so confused! okay so after i take the derivative of the outside functions, what do i do? i ended up with 3(t^4-1)^2 (t^3+1)^4 + (t^4-1)^2 [4(t^3+1)^3]

  19. anonymous
    • 5 years ago
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    You left out derivative of inside function

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