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Gretchen paddles a canoe upstream 3 mi/h. Traveling downstream, she travels at 8 mi/h. What is Gretchen's paddling rate in still water and what is the rate of the current?

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paddling rate in still water- 5.5 mph rate of the current- 2.5 mph
how did u do that
ok. so when he paddles upstream, he's going against the current. If we let x represent his paddling rate in still water and let y represent the rate of the current. When he goes upstream the equation is X-Y=3 and when he goes downstream X+Y=8 when we combine the two equations the Y's cancel out and you get 2X=11. x = 5.5 then you plug 5.5 into one of the equation for x and you find y

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