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anonymous

  • 5 years ago

(x^1/6y^1/3)^-18

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  1. bahrom7893
    • 5 years ago
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    x/2y - 18

  2. anonymous
    • 5 years ago
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    can you show me how you did that?

  3. anonymous
    • 5 years ago
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    he muliplied the exponents

  4. anonymous
    • 5 years ago
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    to equal -18? or multiplied them to the fractions..

  5. anonymous
    • 5 years ago
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    in numerator you have exponent of 1 and in denominiator you have power(exponent) of 1/3 both of them are raised to the power of -18

  6. anonymous
    • 5 years ago
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    so for 1/6= 3/18 and for 1/3= 6/18

  7. bahrom7893
    • 5 years ago
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    woops sorry, i didnt notice to the negative 18

  8. bahrom7893
    • 5 years ago
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    (x^1/6y^1/3)^-18= (x/6y/3)^(-18)= (x/2y)^(-18)= (2y/x)^(18)

  9. bahrom7893
    • 5 years ago
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    wait a second is y^(1/3) or (y^1)/3?

  10. anonymous
    • 5 years ago
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    \[(x/(6y^(1/3))^-18\]

  11. bahrom7893
    • 5 years ago
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    imran that doesnt help lol, well whatever if u have A^b raised to c, its equal to A^(bc)

  12. bahrom7893
    • 5 years ago
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    (A^b)/(A^c) = A^(b-c) (A^b)*(A^c) = A^(b+c)

  13. anonymous
    • 5 years ago
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    hmmm. um...

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