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x/2y - 18

can you show me how you did that?

he muliplied the exponents

to equal -18? or multiplied them to the fractions..

so for 1/6= 3/18 and for 1/3= 6/18

woops sorry, i didnt notice to the negative 18

(x^1/6y^1/3)^-18=
(x/6y/3)^(-18)=
(x/2y)^(-18)=
(2y/x)^(18)

wait a second is y^(1/3) or (y^1)/3?

\[(x/(6y^(1/3))^-18\]

imran that doesnt help lol, well whatever if u have A^b raised to c, its equal to A^(bc)

(A^b)/(A^c) = A^(b-c)
(A^b)*(A^c) = A^(b+c)

hmmm. um...