anonymous
  • anonymous
(x^1/6y^1/3)^-18
Mathematics
schrodinger
  • schrodinger
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bahrom7893
  • bahrom7893
x/2y - 18
anonymous
  • anonymous
can you show me how you did that?
anonymous
  • anonymous
he muliplied the exponents

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anonymous
  • anonymous
to equal -18? or multiplied them to the fractions..
anonymous
  • anonymous
in numerator you have exponent of 1 and in denominiator you have power(exponent) of 1/3 both of them are raised to the power of -18
anonymous
  • anonymous
so for 1/6= 3/18 and for 1/3= 6/18
bahrom7893
  • bahrom7893
woops sorry, i didnt notice to the negative 18
bahrom7893
  • bahrom7893
(x^1/6y^1/3)^-18= (x/6y/3)^(-18)= (x/2y)^(-18)= (2y/x)^(18)
bahrom7893
  • bahrom7893
wait a second is y^(1/3) or (y^1)/3?
anonymous
  • anonymous
\[(x/(6y^(1/3))^-18\]
bahrom7893
  • bahrom7893
imran that doesnt help lol, well whatever if u have A^b raised to c, its equal to A^(bc)
bahrom7893
  • bahrom7893
(A^b)/(A^c) = A^(b-c) (A^b)*(A^c) = A^(b+c)
anonymous
  • anonymous
hmmm. um...

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