anonymous
  • anonymous
Write the equation of the hyperbola in standard form 9x^2 - y^2 - 36x - 6y + 18 = 0
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
It's been a long time since I have done hyperbola's, but I believe you have to complete the square, if that rings any bells for you?
anonymous
  • anonymous
I completed the square and got it down to 9(x-2)^2 -1(y+3)^2 = -5. After this I am supposed to divide each term by -5 correct? If I divide the first term by that it comes to be 9/-5... that doesn't seem right
anonymous
  • anonymous
Yes, as it has to equal 1. and it will be [1(y+3)]/5 - [9(x-2)/5] = 1, which I think is the correct form of a hyperbola (one is negative?)

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anonymous
  • anonymous
so then the center is (2, -3) and a is square root -5 and b is square root 5 so 2.23? I have to find the foci and vertices and graph it also.

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