Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Write the equation of the hyperbola in standard form 9x^2 - y^2 - 36x - 6y + 18 = 0

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

It's been a long time since I have done hyperbola's, but I believe you have to complete the square, if that rings any bells for you?
I completed the square and got it down to 9(x-2)^2 -1(y+3)^2 = -5. After this I am supposed to divide each term by -5 correct? If I divide the first term by that it comes to be 9/-5... that doesn't seem right
Yes, as it has to equal 1. and it will be [1(y+3)]/5 - [9(x-2)/5] = 1, which I think is the correct form of a hyperbola (one is negative?)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

so then the center is (2, -3) and a is square root -5 and b is square root 5 so 2.23? I have to find the foci and vertices and graph it also.

Not the answer you are looking for?

Search for more explanations.

Ask your own question