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anonymous
 5 years ago
F(x)=8th root of (8x^2)sec(4x)... cant figure out the derivitive of this.. any help?
anonymous
 5 years ago
F(x)=8th root of (8x^2)sec(4x)... cant figure out the derivitive of this.. any help?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0try splitting it up into two parts: [(8x^2)^(1/8)][(sec(4x))^(1/8)] Sorry if all those parens get confusing, but basically its the two seperate parts being raised to the 1/8 power and are multiplied.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry the sec(4x) isnt in the root. its being mulitplied by the 8th root of (8x^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well either way, its still just f(x) = ab, so \[\prime\](x) = (a)(db) + (b)(da)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what would the der. of the 8th root of (8x^2) be? i got how the formulas to use are, but i dont know what im doing wrong here...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thats the chain rule. So it would be (1/8)*[(8x^2)^(7/8)]*(2x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i see where i went wrong.. thanks a lot
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