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anonymous

  • 5 years ago

any help at all

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  1. anonymous
    • 5 years ago
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    hey, how's it going?

  2. anonymous
    • 5 years ago
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    nahhhhh

  3. anonymous
    • 5 years ago
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    hey bobeuclid can you help

  4. anonymous
    • 5 years ago
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    with?

  5. anonymous
    • 5 years ago
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    independent and dependent probabilities

  6. anonymous
    • 5 years ago
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    do you have a specific question?

  7. anonymous
    • 5 years ago
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    yea 5 of them

  8. anonymous
    • 5 years ago
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    roberto rolls two six-sided cubes at the same time find the probability that the sum of the two digits is a mutiple of 3

  9. anonymous
    • 5 years ago
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    i'm not sure if there's a better way of doing that then just listing all the possibilities and counting how many are multiples of 3

  10. anonymous
    • 5 years ago
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    with 6 numbers on each die, there are 6*6 = 36 possibilities, but you have to make sure you count 1,2 and 2,1 as two different possibilities

  11. anonymous
    • 5 years ago
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    you could also do something like this.. if the first die is 1, then the next could be 2 or 5. so (probability the first die is 1)(probability the 2nd is 2 or 5) = (1/6)*(2/6)= 2/36

  12. anonymous
    • 5 years ago
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    k a bag contains 3 blue marbles and 5 red marbles samuel chosses a marble at random th with out replacing the marble he chosses another random what is the probability that he chose 2 red marbles and i have to enter it as a fraction

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