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anonymous

  • 5 years ago

if f(x)=sin^2(3-x) then f'(0)????

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  1. anonymous
    • 5 years ago
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    hey, how's it going?

  2. anonymous
    • 5 years ago
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    Hi i really need this answer:)

  3. anonymous
    • 5 years ago
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    take the derivative of (sin(3-x))^2 like it was x^2, you just have to remember to multiply by the derivative of what's inside the "squared"

  4. anonymous
    • 5 years ago
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    oo sick thats so helpful thanks a million

  5. anonymous
    • 5 years ago
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    hah wats the answer just to confirm?

  6. anonymous
    • 5 years ago
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    why dont you give me what you came up with and we'll see if it looks good

  7. anonymous
    • 5 years ago
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    so i know it starts of as 2(sin3-x)

  8. anonymous
    • 5 years ago
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    then multiply by the derivative of sin(3-x)

  9. anonymous
    • 5 years ago
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    so the derivative of sin(3-x) is? uhm cos(3-x)? correct?

  10. anonymous
    • 5 years ago
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    not quite, remember you have to multiply by the derivative of what's inside the sin

  11. anonymous
    • 5 years ago
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    waah i hate calc. ok so the derivative of that is 1?

  12. anonymous
    • 5 years ago
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    is it?

  13. anonymous
    • 5 years ago
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    lol idk im asking u!

  14. anonymous
    • 5 years ago
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    what's the derivative of 3-x, you probably know that

  15. anonymous
    • 5 years ago
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    -1!!!

  16. anonymous
    • 5 years ago
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    good

  17. anonymous
    • 5 years ago
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    so then its 2sin(3-x)(cos3-x)(1)

  18. anonymous
    • 5 years ago
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    what'd we just talk about though?

  19. anonymous
    • 5 years ago
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    usually you wouldn't leave it as times 1 just so you know, that would just go away

  20. anonymous
    • 5 years ago
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    f(x)=sin^2(3-x) f'(x)= 2sin(3-x)(cos (3-x))(-1) Evaluate for 0: f'(0) = -2sin(3-(0))(cos(3-(0)) f'(0) = -2sin(3)cos(3) f'(0) = 0.279415..

  21. anonymous
    • 5 years ago
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    hey iparke

  22. anonymous
    • 5 years ago
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    Hi, Mr. Euclid. He forgot the -1, I have no intention of stealing your thunder ;)

  23. anonymous
    • 5 years ago
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    no i don't care, and yeah i was already telling him but he disappeared

  24. anonymous
    • 5 years ago
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    if you want some math to do here is a test for you http://floridamao.org/PublicPages/TestArchive.aspx?qy=true&category=States&style=Limits+%26+Derivatives&year=2005

  25. anonymous
    • 5 years ago
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    Ooh cool, saved to bookmarks. I really should be doing my area between two curves calc homework, funny that I choose to do other math as an effective self distraction instead of more traditional routes (video games and food). Firefox hates this site, trying it with Chrome now. Love the name by the way. Euclid's Fifth Postulate and hyperbolic geometry ftw.

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