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anonymous
 5 years ago
M & B Transport charges three levels of fares per passenger. on day 1, the total fare was R675 for 25 pensioners, 25 school children and 50 adults. On day 2, the total fare was R432 for 10 school children, 40 adults and 12 pensioners. On day 3, the total fare was R316.50 for 23 adults, 14 oensioners and 10 school children. Model this problem into a system of linear equations
anonymous
 5 years ago
M & B Transport charges three levels of fares per passenger. on day 1, the total fare was R675 for 25 pensioners, 25 school children and 50 adults. On day 2, the total fare was R432 for 10 school children, 40 adults and 12 pensioners. On day 3, the total fare was R316.50 for 23 adults, 14 oensioners and 10 school children. Model this problem into a system of linear equations

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let a=adults c=children and p=pensioners Day 1:675.00=50a+25c+25p Day 2:432.00=40a+10c+12p Day 3:316.50=23a+10c+14p This is your system, do you need help solving it?
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