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anonymous
 5 years ago
Chain rule with e^(x^2)
anonymous
 5 years ago
Chain rule with e^(x^2)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you do it :) ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0derivative of outside times derivative of inside

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just dont get it ... what is the outside and what the inside part here ... and how do i figure that out?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0e^x's derivative is just e^x so e^(x^2)'s derivative is just e^(x^2) then you multiply that by the derivative of x^2 which is 2x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0usually just consider the numbers in the parenthesis as the inside when looking at this function (x+2)^3's derivative would be 3(x+2)^2*1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it would actually be written "(e^x)^2" ? ... which would make "e^x" the inner function?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the (x^2) would be the innermost function.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have to deal with both e^x^2 function and the x^2 function.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And according to the chain rule, you multiply both derivatives together. Is this clear?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^2 is the inner function but it doesnt matter

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now it is ... thank you soooo much. i really really do appreciate it. i have been pondering over this for over an hour by now.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can do derivative of inside times outside or vice versa. Its more on how you define f and g

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0try to see if you can distinguish in many problems the outside and inside then you are all set if you can do that because derivatives are easy from there if you know the rules and how to apply them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha, Saif, without a graphing calc, your problem is difficult. Off topic, I've narrowed f'(θ) to sin(θ) + sin(2θ) = 0 if you can take it from there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea i got it, we arent aloud to use graphing calculators

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oopps, I meant 2sin(θ) + sin(2θ) = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks i gotta get ready, please fan me if i helped

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry ... gotta ask once again. how do you know "x^2" is the inner function here?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its e raised to a parenthesis e^x is the first function and x=x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you have to learn to distinguish between your inside and outside functions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is the innermost function because it is the one closest to x. You cannot not differentiate further.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i really gotta get ready for class so see if IPARKE can help you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you thank you thank you ... big help :)
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