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anonymous

  • 5 years ago

Chain rule with e^(x^2)

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  1. anonymous
    • 5 years ago
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    e(x^2)*2x

  2. anonymous
    • 5 years ago
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    how did you do it :) ?

  3. anonymous
    • 5 years ago
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    derivative of outside times derivative of inside

  4. anonymous
    • 5 years ago
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    f'(g(x)*g'(x)

  5. anonymous
    • 5 years ago
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    i just dont get it ... what is the outside and what the inside part here ... and how do i figure that out?

  6. anonymous
    • 5 years ago
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    e^x's derivative is just e^x so e^(x^2)'s derivative is just e^(x^2) then you multiply that by the derivative of x^2 which is 2x

  7. anonymous
    • 5 years ago
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    usually just consider the numbers in the parenthesis as the inside when looking at this function (x+2)^3's derivative would be 3(x+2)^2*1

  8. anonymous
    • 5 years ago
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    so it would actually be written "(e^x)^2" ? ... which would make "e^x" the inner function?

  9. anonymous
    • 5 years ago
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    the (x^2) would be the innermost function.

  10. anonymous
    • 5 years ago
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    You have to deal with both e^x^2 function and the x^2 function.

  11. anonymous
    • 5 years ago
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    And according to the chain rule, you multiply both derivatives together. Is this clear?

  12. anonymous
    • 5 years ago
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    x^2 is the inner function but it doesnt matter

  13. anonymous
    • 5 years ago
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    now it is ... thank you soooo much. i really really do appreciate it. i have been pondering over this for over an hour by now.

  14. anonymous
    • 5 years ago
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    you can do derivative of inside times outside or vice versa. Its more on how you define f and g

  15. anonymous
    • 5 years ago
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    try to see if you can distinguish in many problems the outside and inside then you are all set if you can do that because derivatives are easy from there if you know the rules and how to apply them

  16. anonymous
    • 5 years ago
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    Haha, Saif, without a graphing calc, your problem is difficult. Off topic, I've narrowed f'(θ) to -sin(θ) + sin(2θ) = 0 if you can take it from there.

  17. anonymous
    • 5 years ago
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    yea i got it, we arent aloud to use graphing calculators

  18. anonymous
    • 5 years ago
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    its 0 and 2pi

  19. anonymous
    • 5 years ago
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    oopps, I meant -2sin(θ) + sin(2θ) = 0

  20. anonymous
    • 5 years ago
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    Oh nice. Good.

  21. anonymous
    • 5 years ago
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    thanks i gotta get ready, please fan me if i helped

  22. anonymous
    • 5 years ago
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    sorry ... gotta ask once again. how do you know "x^2" is the inner function here?

  23. anonymous
    • 5 years ago
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    its e raised to a parenthesis e^x is the first function and x=x^2

  24. anonymous
    • 5 years ago
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    you have to learn to distinguish between your inside and outside functions

  25. anonymous
    • 5 years ago
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    It is the innermost function because it is the one closest to x. You cannot not differentiate further.

  26. anonymous
    • 5 years ago
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    i really gotta get ready for class so see if IPARKE can help you

  27. anonymous
    • 5 years ago
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    thank you thank you thank you ... big help :)

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