## anonymous 5 years ago to find the acceleration vector of x=t√ and y=3t2−2t when t=1 would you just take the derivative of both x and y twice?

1. anonymous

$3t^{2}$

2. anonymous

not 3t2

3. anonymous

yeah if that's the position function

4. anonymous

yeah if that's the position function

5. anonymous

which it would say r(t) =<$\sqrt{t}$,$3t^{2}$>

6. anonymous

sorry trying to work with equation editor hah