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I think it's [-X^3/y^(2)] +[8e^(x)]
Yes. it is, but how ? could you show me?
yeah but give me like 10 15 minutes i'm going to grab something to eat
ok, well you understand that when taking a Sy x is held constant.
okay cool then what's the derivative of lny?
x^3 is constant and that would stay on the top correct? next, What is the derivative of 4y^2
e^x is constant so, what is Sy?
not exactly, the answers that we found previously will be Sy. What I mean by that it Sy :x^3/y +8ye^x. These are the answers you gave me. Do you see how it equals that? If not, we can approach it differently.
So Ssubyy = -x^3/y^2 + 8e^x?
remember "x" is constant so if you want plug in 7 for x just so you get use to the idea
sorry yea that's the answer
Yes.. why are you plugging in 7? I understand Sy = x^3/y + 8ye^x.. I think my question was to find Syy (x,y) =?
oh then you just do a second partial it's the same idea as doing a second derivative and the "7" thing is just case if haven't grasped the idea that the other variable is held constant.
Are you in Calc 3 or DE?
No.. just very basic business calc
cant imagine doing the regular calc :(
you have to do partials?
Yes.. now to find the local extreme for max and min in 3D
I have another one.. I just can't do figure out should I post it separate?
I just fan you.. thanks for your help
I tried to post it.. but it got stuck f(x,y) = x/y = y/x find fxx, fxy, and fyy