a radiator contains 25 quarts of water and antifreeze solution of which 60 percent ..how much of this solution should be drained and replaced with water for the new solution to be 40 percent antifreeze?

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a radiator contains 25 quarts of water and antifreeze solution of which 60 percent ..how much of this solution should be drained and replaced with water for the new solution to be 40 percent antifreeze?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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60% of the original is water or antifreeze?
Ok, here are our facts: 1) 25 quarts in radiator and 60% is antifreeze now or = 25*.60 = 15 quarts are antifreeze 2) We want 40% or = 25*.40 = 10 quarts of antifreeze for our end result 3) So, we need to eliminate 5 quarts of antifreeze to get our answer 4) 5/.6 = 8 and 1/3 quarts I believe that is the answer, take out 8.3333 quarts and replace with water for desired amount

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