anonymous
  • anonymous
I am missing something in my substitution of integrals. For example: Integral of 5x^2cos(x^3)dx u=x^3 du=3x^2dx x^2dx=1/3du. I don't understand where you get the 1/3du.
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
\[u=x ^{3} = du/dx=3x ^{2} = du/3=x ^{2}dx\] You move the 3 from the right side of the equation to the left hand by dividing with 1/3. You're then left with du/3 = x^2dx
anonymous
  • anonymous
If you dont understand what I meant, I'll try to explain further. :)
anonymous
  • anonymous
Thanks I appreciate that!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Good, glad I could help.

Looking for something else?

Not the answer you are looking for? Search for more explanations.