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anonymous
 5 years ago
I am missing something in my substitution of integrals. For example:
Integral of 5x^2cos(x^3)dx
u=x^3 du=3x^2dx x^2dx=1/3du.
I don't understand where you get the 1/3du.
anonymous
 5 years ago
I am missing something in my substitution of integrals. For example: Integral of 5x^2cos(x^3)dx u=x^3 du=3x^2dx x^2dx=1/3du. I don't understand where you get the 1/3du.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[u=x ^{3} = du/dx=3x ^{2} = du/3=x ^{2}dx\] You move the 3 from the right side of the equation to the left hand by dividing with 1/3. You're then left with du/3 = x^2dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you dont understand what I meant, I'll try to explain further. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks I appreciate that!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Good, glad I could help.
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