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anonymous

  • 5 years ago

Factor completely. -5x²y + 10xy - 15xy² a) -5xy(x + 2 + 3y) b) -5xy(x - 2 + 3y) c) 5xy(-x + 2 + 3y)

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  1. anonymous
    • 5 years ago
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    Start by looking for common factors. All the coefficients are multiples of 5 and there are at least one x and one y in each term. So you will be able to factor out 5xy from each term. When you do that, what do you have left?

  2. anonymous
    • 5 years ago
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    Or, try expanding each answer by mutiplying the terms, and see which one give you the starting equation.

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