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anonymous
 5 years ago
Factor completely.
5x²y + 10xy  15xy²
a) 5xy(x + 2 + 3y)
b) 5xy(x  2 + 3y)
c) 5xy(x + 2 + 3y)
anonymous
 5 years ago
Factor completely. 5x²y + 10xy  15xy² a) 5xy(x + 2 + 3y) b) 5xy(x  2 + 3y) c) 5xy(x + 2 + 3y)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Start by looking for common factors. All the coefficients are multiples of 5 and there are at least one x and one y in each term. So you will be able to factor out 5xy from each term. When you do that, what do you have left?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Or, try expanding each answer by mutiplying the terms, and see which one give you the starting equation.
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