Factor completely. -5x²y + 10xy - 15xy² a) -5xy(x + 2 + 3y) b) -5xy(x - 2 + 3y) c) 5xy(-x + 2 + 3y)

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Factor completely. -5x²y + 10xy - 15xy² a) -5xy(x + 2 + 3y) b) -5xy(x - 2 + 3y) c) 5xy(-x + 2 + 3y)

Mathematics
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Start by looking for common factors. All the coefficients are multiples of 5 and there are at least one x and one y in each term. So you will be able to factor out 5xy from each term. When you do that, what do you have left?
Or, try expanding each answer by mutiplying the terms, and see which one give you the starting equation.

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