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anonymous

  • 5 years ago

The average value of F(x)= -1/(x^2) on (1/2,1) is ?.

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  1. bahrom7893
    • 5 years ago
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    Integral from 1/2 to 1 of f(x)dx time 1/(b-a)

  2. bahrom7893
    • 5 years ago
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    so it will be: 1 / (1-1/2) Integral from 1/2 to 1, etc..

  3. anonymous
    • 5 years ago
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    so do i take the derevative or the anti ?

  4. bahrom7893
    • 5 years ago
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    2 Integral from 1/2 to 1 of -1/(x^2) dx

  5. anonymous
    • 5 years ago
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    oh ok so how i thought when i i need to go to an inegral i take the derevative

  6. bahrom7893
    • 5 years ago
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    no u just integrate..

  7. anonymous
    • 5 years ago
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    ok ty again

  8. anonymous
    • 5 years ago
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    the answer im getting is -6 which is not a choice

  9. bahrom7893
    • 5 years ago
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    -1 * 2 = -2

  10. bahrom7893
    • 5 years ago
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    check the integral

  11. anonymous
    • 5 years ago
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    sorry idk what im doing wrong...2(-1/(1/4))-2(-1/1) so -8+2=-6 but that is clearly not right

  12. bahrom7893
    • 5 years ago
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    Integral of -1/x^2 = Int [-1x^(-2) ] = -1 * x^(-2+1)/(-2+1) = x^(-1) from 1/2 to 1

  13. bahrom7893
    • 5 years ago
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    1^(-1) - (1/2)^(-1) = 1 - 2 = -1

  14. bahrom7893
    • 5 years ago
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    then 2*-1 = -2

  15. anonymous
    • 5 years ago
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    haha tyvm it just clicked lol

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