y = 3 - l t-3 l y' = 9 - t^2 The solutions says that only 3 is a critical number. Why not -3 also?

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y = 3 - l t-3 l y' = 9 - t^2 The solutions says that only 3 is a critical number. Why not -3 also?

Mathematics
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of which equation? -3 should also be a critical number of the second equation, but I don't understand how the first equation relates to the problem
well ultimately i have to find the extrema of the y = 3 - l t-3 l ....so i guess i figured that absolute values had something to do with it but i wasn't exactly sure
wait a second.. how did u differentiate it?

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i did what you told me...square the inside and take the square root
but i dont think this will work..
thats how i got y'
uhmm in that case it would work but im not sure about here...
wait it does work..
i honestly have no idea why, ask ur teacher lol
wait, what was the original question?

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