Determine f(x) = [(x-7)^9]/12 using the derivative rules. I don't get his question because the constant 12 in the denominator confuses me when using the product rule.. please help

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Determine f(x) = [(x-7)^9]/12 using the derivative rules. I don't get his question because the constant 12 in the denominator confuses me when using the product rule.. please help

Mathematics
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just take it out.. its a constant u can ignore it and at the end add it again..
do it like 1/12 times derivative of the rest..
1/12 times 9(x-7)^8

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(3/4)(x-7)^8
our teacher told us that we should put 12 as a negative exponent, so 12^(-1) and use the product rule.. :S
u can't do that... its not 12x is it?
You CAN do that, but it's not a good way to do it. Just remember that 12^(-1) is still a constant, so its derivative is 0.
The best bet with constant multipliers, like your 1/12, is to do as bahrom says -- hide the constant, take the derivative of what's left, then put the constant back.
Oh i see. But if I do 12^(-1), does it make a difference if I do (12)^(-1) or 12^(-1) when in the equation?
its the same thing but u wont use product rule for constants.. u probably copied the question wrong..
ANY DIFFERENTIATION RULES ARE FOR VARIABLES OR FUNCTIONS WITH VARIABLES...
this question was on the test and I got it wrong :( after we got it back, she told us that we should use the product rule so yeah.. thanks guys :)
Using product rule on 12^(-1) * (x - 7)^9 gives 0 * (x - 7)^9 + 12^(-1) * 9(x - 7)^8 (and then simplify). It works, but why would you go to the extra trouble?

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