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anonymous

  • 5 years ago

at what vale of x is the line tangent to the graph of y=x^2+3x+5 perpendicular to the line x-2y=5

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  1. bahrom7893
    • 5 years ago
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    find the derivative: y = 2x + 3 Slope is 2 in second case slope is: -2y = -x+5 y = 1/2 x- 5/2

  2. bahrom7893
    • 5 years ago
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    oh wait no...

  3. bahrom7893
    • 5 years ago
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    in second case slope is 1/2, so: 1/2 = 2x + 3

  4. bahrom7893
    • 5 years ago
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    1 = 4x + 6 -5 = 4x x = -5/4, check my arithmetic and answer.. but that was right lol

  5. bahrom7893
    • 5 years ago
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    i just didnt finish it..

  6. anonymous
    • 5 years ago
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    that is not a choice. the choices are -5/2, -2, -1/2, 1/2, and 5/2

  7. bahrom7893
    • 5 years ago
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    oh sorry its not supposed to be 1/2 = 2x + 3 because we are looking for perpendicular so: -2 = 2x + 3 -5 = 2x x = -5/2

  8. anonymous
    • 5 years ago
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    alright ty again ignore this it just helps me to type it out. find the slope of first line and plug it into the y for the second line and solve for x

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