at what vale of x is the line tangent to the graph of y=x^2+3x+5 perpendicular to the line x-2y=5

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at what vale of x is the line tangent to the graph of y=x^2+3x+5 perpendicular to the line x-2y=5

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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find the derivative: y = 2x + 3 Slope is 2 in second case slope is: -2y = -x+5 y = 1/2 x- 5/2
oh wait no...
in second case slope is 1/2, so: 1/2 = 2x + 3

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Other answers:

1 = 4x + 6 -5 = 4x x = -5/4, check my arithmetic and answer.. but that was right lol
i just didnt finish it..
that is not a choice. the choices are -5/2, -2, -1/2, 1/2, and 5/2
oh sorry its not supposed to be 1/2 = 2x + 3 because we are looking for perpendicular so: -2 = 2x + 3 -5 = 2x x = -5/2
alright ty again ignore this it just helps me to type it out. find the slope of first line and plug it into the y for the second line and solve for x

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