Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

Set X has x members and set Y has y members. Set Z consists of all members that are in either set X or set Y with the exception of the k common members (k>0). Which of the following represents the number of members in set Z? x+y-k or x+y-2k or x+y+k or 2x+2y-2k

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- anonymous

- chestercat

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

If you have a bag X of x pieces of fruit and a bag Y of y pieces of fruit and k fruit are found in both bags, then combining the bags and taking away the fruit means that you take all of the fruit from X and put them with all of the fruit from Y. Then you have to take away the k common fruit from each bag. If you take k fruit from two bags, then you have three k.
The answer is x+y-k-k
I know. I'm pretty good at math ... and analorgies.

Looking for something else?

Not the answer you are looking for? Search for more explanations.