A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

hey...lim as x->1 of ([1/(x-1)]-[1/lnx])...I know it is [(1/0)-(1/0)], what do I do from there?

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Bad way to start. Get a common denominator: [(1*lnx)-(1*(x-1))]/[(x-1)lnx]

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Let a=1/0 a-a=0. Therefore, your answer is 0.

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I got -1/2, anyone agree?

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you got it right. It is -1/2. Using hopitals rule.

  5. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Harwin: No can do. 1/0 = infinity. Infinity - infinity is one of the 7 indeterminate forms. it's not 0. Esperantist is correct. Get a common denominator. Then it may be possible to use l'Hopital's rule.

  6. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Actually, this is probably the best way-> http://www.wolframalpha.com/input/?i=lim+x-%3E1+%28%28 [1%2F%28x-1%29]-[1%2Flnx]%29%29

  7. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks, yeah using hopitals rule twice

  8. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oops, the url broke

  9. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that wolframalpha thing is realllly nice

  10. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh damn, you're right. Man I suck at math.

  11. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no, indeterminants are just really weird

  12. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Harwin -- easy mistake to make. My students do it all the time.

  13. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I was joking.

  14. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wolframalpha.com (in case you haven't heard of it already)--it helps a lot with understanding IMO

  15. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    k thanks Esperantist, i'll check it out

  16. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If anyone's still around I have sin(x)/[1-cos(x)], I got -1/2 again, is that right?

  17. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what does it approach to?

  18. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.