anonymous
  • anonymous
(5-x)^1/2 = x+1 (show steps plz!)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
How about I take you through it step by step instead?
anonymous
  • anonymous
sounds good to me.
anonymous
  • anonymous
Okay, so it's easier if you get rid of the 1/2 exponent, so square both sides.

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anonymous
  • anonymous
i did that and got 5-x= x^2+2x+1
anonymous
  • anonymous
then set everything equal to 0
anonymous
  • anonymous
0=x^2+3x-4
anonymous
  • anonymous
factor that
anonymous
  • anonymous
everything after is a blurr
anonymous
  • anonymous
ok
anonymous
  • anonymous
ummm yeah. i have no idea.
anonymous
  • anonymous
Quadratic formula....
anonymous
  • anonymous
all right. so when you factor you're going to get (x+y)(x-z)=0 where y and z are numbers, possibly the same number. You know you're going to subtract one of them and add one of them because if you look at the number that has no x's in it (-4) you subtract it. Did that much make sense?
anonymous
  • anonymous
You can also use the quadratic formula, but I find factoring it easier.
anonymous
  • anonymous
Factoring is easier, but for people who can't do that sort of factoring in their head, the quadratic formula is handy.
anonymous
  • anonymous
Or at least it's easier if you understand factoring, which is definitely something you learn by practicing.
anonymous
  • anonymous
Exactly!
anonymous
  • anonymous
is that -(b)sqrt(b^2)-4(a)(c)/ 2(a)?
anonymous
  • anonymous
That's true, I completely agree with you, Harwin. Sorry, slow typer apparently!
anonymous
  • anonymous
(-b + sqrt(b^2 - 4ac))/2a and (-b - sqrt(b^2 - 4ac))/2a
anonymous
  • anonymous
oh whoops yeah for got the +-
anonymous
  • anonymous
Anyway, snooozzzzze knows how to get you through it. I'll give the show back to him.
anonymous
  • anonymous
haha her, but that's ok. :) Do you want to use the quadractic formula, or try factoring?
anonymous
  • anonymous
so does \[-11+-\sqrt{73}/8\] sound like its on the right track?
anonymous
  • anonymous
Oh sorry. English really needs a genderless pronoun other than "it"....
anonymous
  • anonymous
ha
anonymous
  • anonymous
Use the quadractic formula on this equation: 0=x^2+3x-4
anonymous
  • anonymous
oh shoot sorry i was looking at another equation
anonymous
  • anonymous
That's very true. Not sure calling me it would have been better, but in any case it's not a big deal at all. RedCarr: No problem at all. Just try again with the right equation this time.
anonymous
  • anonymous
how about \[-3+-\sqrt{57}/2\]?
anonymous
  • anonymous
I'm not sure how you got the 57, but it's wrong.
anonymous
  • anonymous
also, when you do it, make sure that you know that the 2 is over everything, not just the squareroot part.
anonymous
  • anonymous
in place of the 57 would it be 25?
anonymous
  • anonymous
that looks right to me.
anonymous
  • anonymous
so x=1 and X=-8?
anonymous
  • anonymous
No, this is what you should get: (−3+5)/2 (−3-5)/2
anonymous
  • anonymous
? i meant -4 but why the parenthesis?
anonymous
  • anonymous
because otherwise you'd have written -3+5/2 which would simplify to -3+2.5=-0.5
anonymous
  • anonymous
but yes, -4 and 1 is correct.
anonymous
  • anonymous
except look at your original problem to see if they work.
anonymous
  • anonymous
do you have a graphing calc with you? if you do plug in \[-3+\sqrt{25}\]
anonymous
  • anonymous
because actually only one of them works in that case.
anonymous
  • anonymous
I don't have a calculator, but I can visualize it.
anonymous
  • anonymous
yeah only 1 does not the -4
anonymous
  • anonymous
right, and that's because when we started the problem we squared both sides, which gave us the extra answer.
anonymous
  • anonymous
well when i plugged it in my answer was 2. then i divided that 2 by 2 to get 1 which is the only answer.
anonymous
  • anonymous
I'm sorry, could you restate that? I'm not really sure what you mean.

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