The position function of an object that moves in a straight line is s(t) = 1 + 2t - [8/(t^2 +1)], 0≤t≤2. Calculate the maximum and minimum velocities of the object over the given time interval.
Answer: min is 2, max is 2 + 3√3.
How do you solve this? I know that you have to find the second derivative. When I do that though, I get t=±√(1/3)..

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