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anonymous

  • 5 years ago

identify critical points 4x^4 - 16x^2 +17

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  1. anonymous
    • 5 years ago
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    When the derivative equals zero.

  2. anonymous
    • 5 years ago
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    find the first derivative then set it equal to 0 to find the critical numbers

  3. anonymous
    • 5 years ago
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    derivate is 16x^3 - 32x^2?

  4. anonymous
    • 5 years ago
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    a little off 16x^3-32x

  5. anonymous
    • 5 years ago
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    then 16x^2-32x=0 factor 16x out of both terms, then set each factor = 0

  6. anonymous
    • 5 years ago
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    sorry mistyped

  7. anonymous
    • 5 years ago
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    okay so i got root two. but that's only the max

  8. anonymous
    • 5 years ago
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    16x(x-2)=0 16x=0, would also get you the other one, x = 0

  9. anonymous
    • 5 years ago
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    i see thanks

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spraguer (Moderator)
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