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anonymous
 5 years ago
find: a) (f+g)(x) b) (fg)(x) c) (fg)(x) d) (f/g)(x)
what is the domain of f/g?
f(x)=x/x+1 g(x)=x^3
anonymous
 5 years ago
find: a) (f+g)(x) b) (fg)(x) c) (fg)(x) d) (f/g)(x) what is the domain of f/g? f(x)=x/x+1 g(x)=x^3

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right, we'll try this out. Slowly.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you substitute (f+g) with the actual functions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a: ((x/x+1)+(x^3))(x) Distribute the outside x. x^2/x+1 + x^4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0b) We're going to replace f and g again. (fg)(x) ((x/x+1)(x^3))(x) Distribute again. x^2/x+1  x^4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you handle part C now?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0excuse me mate is it like that (f+g)(x) should be f(x)+g(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it should be just x/(x+1)+x^3 for the question a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ohh haha. Yes. That does make sense. I didn't even think to consider she was saying f plus g OF x. I was just doing multiplication.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No no, ignore me. That is right. What was I thinking.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0b) f(x)  g(x) Therefore x/(x+1) x^3 (x(x^3(x+1)))/(x+1) (xx^4x^3)/(x+1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0c)f(g(x)) x^3/(x^3+1) because we are substituting x^3 in the function f(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did u understand c jane

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0d) f(x) / g(x) (x/(x+1))/x^3) 1/(x^2(x+1))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0domain for the question is all real values of x excluding 0 and 1, because if we put 0 or 1 for x then f(x)/g(x) would become infinity since we get a 0 in the dinominator
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