anonymous
  • anonymous
find: a) (f+g)(x) b) (f-g)(x) c) (fg)(x) d) (f/g)(x) what is the domain of f/g? f(x)=x/x+1 g(x)=x^3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Right, we'll try this out. Slowly.
anonymous
  • anonymous
can you substitute (f+g) with the actual functions?
anonymous
  • anonymous
a)x^4/(x+1) +1

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More answers

anonymous
  • anonymous
a: ((x/x+1)+(x^3))(x) Distribute the outside x. x^2/x+1 + x^4
anonymous
  • anonymous
b) We're going to replace f and g again. (f-g)(x) ((x/x+1)-(x^3))(x) Distribute again. x^2/x+1 - x^4
anonymous
  • anonymous
Can you handle part C now?
anonymous
  • anonymous
Give it a try.
anonymous
  • anonymous
excuse me mate is it like that (f+g)(x) should be f(x)+g(x)
anonymous
  • anonymous
so it should be just x/(x+1)+x^3 for the question a
anonymous
  • anonymous
Ohh haha. Yes. That does make sense. I didn't even think to consider she was saying f plus g OF x. I was just doing multiplication.
anonymous
  • anonymous
No no, ignore me. That is right. What was I thinking.
anonymous
  • anonymous
b) f(x) - g(x) Therefore x/(x+1) -x^3 (x-(x^3(x+1)))/(x+1) (x-x^4-x^3)/(x+1)
anonymous
  • anonymous
c)f(g(x)) x^3/(x^3+1) because we are substituting x^3 in the function f(x)
anonymous
  • anonymous
did u understand c jane
anonymous
  • anonymous
d) f(x) / g(x) (x/(x+1))/x^3) 1/(x^2(x+1))
anonymous
  • anonymous
domain for the question is all real values of x excluding 0 and -1, because if we put 0 or -1 for x then f(x)/g(x) would become infinity since we get a 0 in the dinominator
anonymous
  • anonymous
that's all,its easy
anonymous
  • anonymous
Yes easy

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