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Right, we'll try this out. Slowly.
can you substitute (f+g) with the actual functions?
a: ((x/x+1)+(x^3))(x) Distribute the outside x. x^2/x+1 + x^4
b) We're going to replace f and g again. (f-g)(x) ((x/x+1)-(x^3))(x) Distribute again. x^2/x+1 - x^4
Can you handle part C now?
Give it a try.
excuse me mate is it like that (f+g)(x) should be f(x)+g(x)
so it should be just x/(x+1)+x^3 for the question a
Ohh haha. Yes. That does make sense. I didn't even think to consider she was saying f plus g OF x. I was just doing multiplication.
No no, ignore me. That is right. What was I thinking.
b) f(x) - g(x) Therefore x/(x+1) -x^3 (x-(x^3(x+1)))/(x+1) (x-x^4-x^3)/(x+1)
c)f(g(x)) x^3/(x^3+1) because we are substituting x^3 in the function f(x)
did u understand c jane
d) f(x) / g(x) (x/(x+1))/x^3) 1/(x^2(x+1))
domain for the question is all real values of x excluding 0 and -1, because if we put 0 or -1 for x then f(x)/g(x) would become infinity since we get a 0 in the dinominator
that's all,its easy