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anonymous
 5 years ago
Integral of 5x^3 dx / 14x^4
We have to solve this by substitution. I took 14x^4 as my value of u. Then I found du/dx =8x^3
du = 8x^3 dx
8du = x^3 dx
I don't know what to so next or how to substitute correctly. Am I even on the right track??
anonymous
 5 years ago
Integral of 5x^3 dx / 14x^4 We have to solve this by substitution. I took 14x^4 as my value of u. Then I found du/dx =8x^3 du = 8x^3 dx 8du = x^3 dx I don't know what to so next or how to substitute correctly. Am I even on the right track??

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, you're right in making u=14x^4 which would make du=8x^3dx Because your coefficient is 5 and not 8, you should multiply everything in the integral by 8/5 and divide by it outside the integral, which is the same as multiplying by 5/8 This will make you be taking the integral of (5/8)(1/u)(du) Did that actually make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Indeed it did! Thank you very much!!
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