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anonymous

  • 5 years ago

simplify: 4 over 2 + radical 3

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  1. anonymous
    • 5 years ago
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    So 4/2=2. So 2+radical3 is simplified, since you can not do anything more with the radical 3

  2. anonymous
    • 5 years ago
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    \[4\div \left( 2 + \sqrt{3} \right)\]

  3. anonymous
    • 5 years ago
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    Is that what you meant?

  4. anonymous
    • 5 years ago
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    its 4 over 2+ radical 3

  5. anonymous
    • 5 years ago
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    yes

  6. anonymous
    • 5 years ago
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    Or did you mean 4/(2+rad3)

  7. anonymous
    • 5 years ago
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    Ah nevermind, my computer loaded up what dashingblock typed earlier. :)

  8. anonymous
    • 5 years ago
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    Okay, so you can't have a radical in the denominator. If you multiply the radical by itself directly, then you get just the number under the radical. But you have to make sure whatever you're multiplying by is a one. Let me show you in mathematical terms. Dr. Pepper, shall I take this one and you can help another? :P

  9. anonymous
    • 5 years ago
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    So: 2 ________ 2 + rad3 Rad 3 times rad 3 gives you rad 9, right?

  10. anonymous
    • 5 years ago
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    \[\sqrt{9}\]And that is equal to the number three since the square root of 9 is 3. This means you now have: 2 _____ 2+3 So really, 2 ____ 5 But there's a problem because if you are going to multiply one part of a fraction (say, the denominator) by something, you must multiply the other part (numerator) by the same thing.

  11. anonymous
    • 5 years ago
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    So now its: 2 multiplied by \[\sqrt{3}\] __________________ 5

  12. anonymous
    • 5 years ago
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    Oh, dang, please replace all of my numerator 2 with numerator 4! Whoops, sorry! This is the correct answer : \[4\sqrt{3} \div 5\]

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