need to find an equation. m=2/3, (5,-2) I got y-(-2)=(2/3)(x-5) and then y+2=2/3x+2 what next?

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need to find an equation. m=2/3, (5,-2) I got y-(-2)=(2/3)(x-5) and then y+2=2/3x+2 what next?

Mathematics
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shouldn't it be y+2=2x/3-10/3 not y+2=2x/3+2?
I don't know for sure that is why I am asking.
ok well when you multiplied it out it was supposed to be what I just gave you. And your next step would then be to subtract 2...6/3 from both sides. That is if your answer should be in y=mx+b format.

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ok i am still confused
ok what is your confusion?
well what you are telling me is different than what they are telling me in my book.
what are they telling you in your book?
what i just put on here except they are telling is to subtract 1 from each side
So it's telling you to subtract 1 from both sides as the next step?
ya and that is why I figured I would ask
I'm not sure I understand the question because I would have approached it differently to begin with. I would have taken y=mx+b and plugged in your m value of 2/3 and then your point (5, -2) to get -2=2/3(5)+b. Then I would solve for b and get -16/3. Then the equation for the line would be y=(2/3)x-16/3.
From the info I gave I am suppose to come up with an equation.
the info you gave being a slope of 2/3 and you're finding the equation of the line passing through the point (5,-2), right?
ya in the format of y=mx+b
well I got the answer y=(2/3)x-16/3 with that given information
and i haven't a clue why the book would tell you to subtract 1 from each side. Are you looking at an example? Where did you get the subtract 1 thing from?
I just realized how late it is. I have to go to a 6:00 class and I have to leave now to get there on time. I'm really sorry, but I have to go!

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