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anonymous
 5 years ago
ok...here we go with the ladder! Related Rates. 24' ladder hanging over a 7' fence  what is the rate the top is decending to the ground when the base is 7' away from the fence. I think I am trying to cal the rate change of the triangle? This is not a simple scenario....help! Thanks
anonymous
 5 years ago
ok...here we go with the ladder! Related Rates. 24' ladder hanging over a 7' fence  what is the rate the top is decending to the ground when the base is 7' away from the fence. I think I am trying to cal the rate change of the triangle? This is not a simple scenario....help! Thanks

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Looks like we need to use some implicit differentiation here. So we know the length of the ladder, 24 feet, and it rests over a 7 foot wall, so the total height of the ladder against the wall would be y+7. Using the pathagorean theorem, we have, \[24^2= x^2+(y+7)^2\] We differentiate with respect to x and get, \[0=2x+2(y+7)dy/dx\] We know the length of the ladder is not changing, so it's rate of change is zero. Now you can solve for dy/dx and you will have the rate of change of the y position of the ladder when you sub in 7 for x.
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