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anonymous
 5 years ago
At what point on y=(3)/(x1) does the tangent pass through the origin? Helpp!!!
anonymous
 5 years ago
At what point on y=(3)/(x1) does the tangent pass through the origin? Helpp!!!

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First question: are you in calc 1?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i think lol high school calculus

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Anyway, I am going to assume you guys are learnign about derivatives, correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep i found the derivative but idk what else to do afterwards

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So what technically (in case if your teacher did not make this clear), a derivative of a curve, is technically the slope, so to speak.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So if you were to, i dont know, set it up in some sort of linear function using your (0,0) point I would imagine you could find an equation. :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.00=m(0)+b, solve for b.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the thing is i have to find the point

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hold on, comp acting funny

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ah i see what you're asking.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y =(3)/(x1) So y ' = 3/(x1)^2 let the point of tangency (a, y(a)) ==> (a, (3)/(x1)))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So the sloope at that point will be 3/(a1)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So the equation of tangent with slope 3/(a1)^2 and passing through (a, (3)/(x1)) is y (3)/(x1)= 3/(a1)^2* (x  a)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Since (0,0) is a point in this line you can substitute 0 for x and 0 for y.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So we have 3/(1)=3/(a1)^2*(a)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03=(3a)/(a1)^2 3(a1)^2=3a 3(a^22a+1)=3a a^22a+1=a a^23a+1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In theory that should have worked... where did i make an algebraic mistake?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok ill try do it the same way u did

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And hopefully you dont run into the error i am running into. This is strange.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i got the answer thank you so much for pointing out what to do i have a test tomorrow and i was literally freaking out so ur a lifesaver

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, I am happy to hear my idea pushed you the right direction.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Also, some pointers on calc in high school (thats when I took it):

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Breathe and practice similar problems =D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Did the process make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep it did and besides i got the correct answer :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yay! Well I wish you luck on your exam, be sure to get some sleep (always a good thing).
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