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he66666
 5 years ago
The position function of an object moving horizontally along a straight line as a function of time is s(t) = t^2 3t +2, t≥0, in metres, at time t, in seconds.
a) Determine the speed of the object when the position is 0.
answer: 1 m/s
Isn't the answer 1 m/s AND 1m/s? That's what I get when I plug in t=2 and t=1 in the function
b) When does the object move to the left?
answer: between 0s and 1.5s
Does between mean that it includes the value? since the question states that t≥0, shouldn't the answer be 0≤t<(3/2)?
he66666
 5 years ago
The position function of an object moving horizontally along a straight line as a function of time is s(t) = t^2 3t +2, t≥0, in metres, at time t, in seconds. a) Determine the speed of the object when the position is 0. answer: 1 m/s Isn't the answer 1 m/s AND 1m/s? That's what I get when I plug in t=2 and t=1 in the function b) When does the object move to the left? answer: between 0s and 1.5s Does between mean that it includes the value? since the question states that t≥0, shouldn't the answer be 0≤t<(3/2)?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can see your point of view for both of these questions. For the first one the reason why they may be saying that only 1 m/s is the answer is because speed is the absolute value of velocity (which is what you get when you say 1 m/s and 1m/s). So the absolute value of 1 is 1 and the absolute value of 1 is 1 as well. Or at least that is the only reasoning I can come up with.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0As for your second question, I believe you are correct in saying that it is inclusion so \[0\le t \le 3/2\] Since technically on the graph of the position it is decresing from 0 to 1.5 and increasing from 1.5 to infinity.

he66666
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks so much! I understand it now :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Glad that I could clarify.
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