## anonymous 5 years ago arch is shape like a arch can be parabola the arch can be appriximated by y =630-0.00635x2 both x and y distance in ft origin is the point on the ground below the arch apex find the x intercepts and how wide is the arch base

Well, to find the x intercepts, we need to find x when y=0. $0=630-.00635x^2$ Solving for x you should get, $x^2=630\div.00635$ Because the arch is a parabola, we can use symmetry to find the length of the base. Remember when taking the square root of a number to include +/-. $x=+/-\sqrt{99212.6}$ Bacause of symmetry, the distance is simply 2 times x, which should be 629.961 feet.