what is the derivitive of e^(x^5-4x)

- anonymous

what is the derivitive of e^(x^5-4x)

- schrodinger

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- anonymous

\[e ^{x^5-4x}(5x^4-4)\]

- anonymous

what would the second derivitive be?

- anonymous

use the product rule and chain rule on branlegr's equation

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## More answers

- anonymous

hmmm tried that... must not be typing right

- anonymous

e^(x^5-4x)*5x^4-4)

- anonymous

\[e^{x^5-4x}(20x+(5x^4-4)^2)\]

- anonymous

you dont need the product rule, all you need is chain

- anonymous

derivative of the outside times the derivative of the inside

- anonymous

e^x's derivative is e^x so consider x = x^5-4x

- anonymous

which becomes your inside function that you take the derivative and multiply it by

- anonymous

\[e^{x^5−4x}(20x^3+(5x^4−4)^2)\]
I made a mistake... this is it

- anonymous

thats wrong. You are making it more complicated then it has to be
Its just the derivative times the inside. Hes just entering it wrong Im pretty sure

- anonymous

nadeen is right ... thank you much

- anonymous

derivative of the outside times the derivative of the inside i mean*

- anonymous

No, you must use the product rule to find second derivative.

- anonymous

why are you taking the second derivative, Is that the problem?

- anonymous

yea nadeem is right, I didnt realize you needed the second derivative

- anonymous

Thanks....... for a second I thought I was going crazy

- anonymous

yes higher order

- anonymous

you never specified the problem correctly creeg
no Nadeem, you are 100% correct

- anonymous

cool

- anonymous

ln(15x7)−3y3=x3ey... guys want to help with thsi one .. i just need y prime.. cant get a right answer... tried like 1 hr on this stupid problem..

- anonymous

15x^7

- anonymous

I thought i did that already

- anonymous

no this is just an implicit problem

- anonymous

ln(x)= 1/x is the derivative
umm -9y^2 y' is that derivative
3x^2
ey wont you have to do product rule

- anonymous

sorry this is it.. ln(15x^7)-3y^3=(x^3)(e^y)

- anonymous

\[(7−3x^3e^y)/x(9y^2+x^3e^y)=dy/dx\] is this not it?

- anonymous

just isolate y' this is easy

- anonymous

yes i know what to do saif... im just having a hard time either typing it in or im missing something

- anonymous

is this webassign?

- anonymous

cause webassign always messes up everything. I feel your pain

- anonymous

webwork .. prob the same.. i hate it

- anonymous

yea i bet!

- anonymous

and nadeen thats not the answer

- anonymous

What is it?

- anonymous

I dont understand Saif623 check my answer out and see if it makes sence...... you are suppose to differentiate implicitly... right?

- anonymous

my bad nadeen .. your right... i had to just fix a typo..

- anonymous

Man..........yall are trippin!

- anonymous

yea i got the same nadeem

- anonymous

you are right

- anonymous

lmao

- anonymous

lol... its been a long week.. how about tangent lines? e^(yx^3)−x(y^3+1)=9 at (-8,0)

- anonymous

i have finals on friday and I am doing your hw

- anonymous

lol

- anonymous

same here Bro...wtf... lol

- anonymous

that one will make my head explode with all my other studying im doing right now

- anonymous

sorry man you are on your own

- anonymous

ya i just got it .. nevermind.. thanks a lot you two.. big help... good luck with the finals..

- anonymous

no problem and Thanks Im gonna need it. 3 finals back to back

- anonymous

ya thats my schedule tomarrow..

- anonymous

Professors are so annoying. I have a webassign due to. Thank GOD I asked for an extension so its due after my finals

- anonymous

my math prof gave a quiz yesterday and this hw is do right now and the test is tomarrow night.. bad planning on their part .. whole class is pissed..

- anonymous

i bet! my professor randomly gives webassign homework so we will have like an hour to do it. Gets annoying

- anonymous

Lol when I see people asking on here problems to do with adding fractions. I wish that was my hw lol!

- anonymous

damn that would be frustrating.. lol ya ... alright well thanks again.. i got some more studying to do so ill cya around on here .. late

- anonymous

lates I got a lot of studying ahead of me to. Good Luck with the exam tomorrow

- anonymous

thanks ...

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