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anonymous
 5 years ago
Use the Pythagorean Theorem to find the distance to the nearest tenth, between F(9, 5) and G(2, 2). (Hint: Place F and G on the coordinate plane. Then sketch a triangle with FG as the hypotenuse.)
anonymous
 5 years ago
Use the Pythagorean Theorem to find the distance to the nearest tenth, between F(9, 5) and G(2, 2). (Hint: Place F and G on the coordinate plane. Then sketch a triangle with FG as the hypotenuse.)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Put a point H on (9, 2). Sketch a triangle out of the three points. Distance between (2, 2) and (9, 2) is going to be 11. Distance between (9, 2) and (9, 5) is going to be 3. These correspond to the a and b of the Pythagorean Theorem \[c^2=a^2+b^2\] \[c = \sqrt{11^2+3^2}=\sqrt{130}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Square root of 130 is 11.4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well pythagorean theorem is a^2+b^2=c^2 so a is 11 because you do the distance between 9 and 2 then b is the distance between 5 and 2 which is 3 so you get 11^2 = 121 and 3^2 = 9 so sqrt of 130 is the answer which is between 11 and 12
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