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anonymous

  • 5 years ago

prove that 4^k > k^3

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  1. anonymous
    • 5 years ago
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    for k integer?

  2. anonymous
    • 5 years ago
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    i mean k positive integer?

  3. anonymous
    • 5 years ago
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    cantor it would work for non integers to... trying to think how you would prove it though

  4. anonymous
    • 5 years ago
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    sorry..should have mentioned the conditions...k are positive integers...need to prove by mathematical induction..

  5. anonymous
    • 5 years ago
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    thought so..... I was about to say induction

  6. anonymous
    • 5 years ago
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    well when k = 0 the expression becomes 4^0>0^3 which becomes 1>0 which is true and as the value of k increases the first side of the expression increases at a much more rapid rate so that is why this is going to be true for all positive integers of k

  7. anonymous
    • 5 years ago
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    check this page out http://answers.yahoo.com/question/index?qid=20101204110027AASBIgf it is similar to your problem and should walk you through the process, which is a long process

  8. anonymous
    • 5 years ago
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    yes Nikko..that is true. but this is by intuition...proof by induction is bit complicated

  9. anonymous
    • 5 years ago
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    give the base case, inductive hypothesis , and then prove by induction

  10. anonymous
    • 5 years ago
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    thank you Nadeem...i'll go through the site

  11. anonymous
    • 5 years ago
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    the only difference is that they had a parameter where \[n \ge5\]

  12. anonymous
    • 5 years ago
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    give me a sec to work this out

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