anonymous
  • anonymous
prove that 4^k > k^3
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
for k integer?
anonymous
  • anonymous
i mean k positive integer?
anonymous
  • anonymous
cantor it would work for non integers to... trying to think how you would prove it though

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anonymous
  • anonymous
sorry..should have mentioned the conditions...k are positive integers...need to prove by mathematical induction..
anonymous
  • anonymous
thought so..... I was about to say induction
anonymous
  • anonymous
well when k = 0 the expression becomes 4^0>0^3 which becomes 1>0 which is true and as the value of k increases the first side of the expression increases at a much more rapid rate so that is why this is going to be true for all positive integers of k
anonymous
  • anonymous
check this page out http://answers.yahoo.com/question/index?qid=20101204110027AASBIgf it is similar to your problem and should walk you through the process, which is a long process
anonymous
  • anonymous
yes Nikko..that is true. but this is by intuition...proof by induction is bit complicated
anonymous
  • anonymous
give the base case, inductive hypothesis , and then prove by induction
anonymous
  • anonymous
thank you Nadeem...i'll go through the site
anonymous
  • anonymous
the only difference is that they had a parameter where \[n \ge5\]
anonymous
  • anonymous
give me a sec to work this out

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