## anonymous 5 years ago the integral of dt/t times root t

1. anonymous

thats just ... ln t * root t

2. anonymous

thanks

3. anonymous

That's not correct though. If I understood correctly and you have this integral: $\int\limits dt/t \sqrt{t}$ You solve it by using the exponent properties. This will add up to: $\int\limits dt/ t^{3/2}$ Treating this as $\int\limits t^{-3/2}$ you should be able to integrate from there. If you derivate ln(t)*t you get $\sqrt{x}/x + \ln(x)/2\sqrt{x}$ Which is not the same integral.

4. anonymous

ln(t)*root(t) obviously, misstype..

5. anonymous

That's what I was thinking as well but I think rockrmol5 means: $\int\limits_{}\sqrt{t}/t dt=\int\limits_{}t^{-1/2}=2t^{1/2}+c$ either way one of us is right bc ln(t)*root(t) doesn't make any sense