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anonymous
 5 years ago
the integral of dt/t times root t
anonymous
 5 years ago
the integral of dt/t times root t

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats just ... ln t * root t

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's not correct though. If I understood correctly and you have this integral: \[\int\limits dt/t \sqrt{t}\] You solve it by using the exponent properties. This will add up to: \[\int\limits dt/ t^{3/2}\] Treating this as \[\int\limits t^{3/2}\] you should be able to integrate from there. If you derivate ln(t)*t you get \[\sqrt{x}/x + \ln(x)/2\sqrt{x}\] Which is not the same integral.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ln(t)*root(t) obviously, misstype..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's what I was thinking as well but I think rockrmol5 means: \[\int\limits_{}\sqrt{t}/t dt=\int\limits_{}t^{1/2}=2t^{1/2}+c\] either way one of us is right bc ln(t)*root(t) doesn't make any sense
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