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anonymous

  • 5 years ago

I'm no good at factoring. Suggestions?

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  1. anonymous
    • 5 years ago
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    http://www.purplemath.com/modules/factnumb.htm Read the whole page, all topics will help you. :)

  2. anonymous
    • 5 years ago
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    What shall I do with the equation 24x^2-8x?

  3. bahrom7893
    • 5 years ago
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    take 8x out: 8x(3x-1)

  4. anonymous
    • 5 years ago
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    Could you help me with this one? x^3-5x^2-9x+45

  5. bahrom7893
    • 5 years ago
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    first take a look at what can u factor out.. first part looks like x^2 can be taken out and in the 2nd, 9 can be taken out...

  6. bahrom7893
    • 5 years ago
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    x^2(x-5) + 9(-x+5), now if you observe that once you take -1 out in 9(-x+5) you will get an (x-5) there.. so

  7. bahrom7893
    • 5 years ago
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    x^2(x-5) + 9(-x+5) x^2(x-5) -9(x-5) Now take x-5 out: (x-5)[x^2-9]

  8. bahrom7893
    • 5 years ago
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    now x^2 - 9 is in the form a^2 - b^2 = (a-b)(a+b) x^2-9 = x^2 - 3^2 = (x-3)(x+3) (x-5)[x^2-9] = (x-5)(x-3)(x+3)

  9. anonymous
    • 5 years ago
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    Yeah now I'm lost.

  10. bahrom7893
    • 5 years ago
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    where exactly are you lost? which step?

  11. anonymous
    • 5 years ago
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    Where did the x^2-3^2 come from?

  12. bahrom7893
    • 5 years ago
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    9 = 3^2

  13. anonymous
    • 5 years ago
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    Wouldn't the two (x-5)s cancel out? I figured you'd be left with x^2-9 and take the square root of the nine to end up with x^2(x+3)(x-3).

  14. bahrom7893
    • 5 years ago
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    U can't just drop it, I took it out..

  15. bahrom7893
    • 5 years ago
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    x^2(x-5) -9(x-5)=(x-5)[x^2-9] = (x-5)(x-3)(x+3)

  16. anonymous
    • 5 years ago
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    So one of the x-5s goes away, then? And you're left with (x-5)(x-3)(x+3) <- that bit?

  17. bahrom7893
    • 5 years ago
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    yes and the x-5 doesnt go away anywhere, I just take it outside of big parenthesis, just like you would do: 3x-3y = 3(x-y), see the same term comes out, x^2(x-5) -9(x-5) = (x-5)(x^2 * 1 - 9 * 1)

  18. bahrom7893
    • 5 years ago
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    x^2(x-5) -9(x-5) = (x-5)(x^2 * 1 - 9 * 1) = (x-5)(x^2-9)

  19. anonymous
    • 5 years ago
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    I see.

  20. bahrom7893
    • 5 years ago
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    any more questions?

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