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anonymous
 5 years ago
I'm no good at factoring. Suggestions?
anonymous
 5 years ago
I'm no good at factoring. Suggestions?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.purplemath.com/modules/factnumb.htm Read the whole page, all topics will help you. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What shall I do with the equation 24x^28x?

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0take 8x out: 8x(3x1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Could you help me with this one? x^35x^29x+45

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0first take a look at what can u factor out.. first part looks like x^2 can be taken out and in the 2nd, 9 can be taken out...

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0x^2(x5) + 9(x+5), now if you observe that once you take 1 out in 9(x+5) you will get an (x5) there.. so

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0x^2(x5) + 9(x+5) x^2(x5) 9(x5) Now take x5 out: (x5)[x^29]

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0now x^2  9 is in the form a^2  b^2 = (ab)(a+b) x^29 = x^2  3^2 = (x3)(x+3) (x5)[x^29] = (x5)(x3)(x+3)

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0where exactly are you lost? which step?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Where did the x^23^2 come from?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wouldn't the two (x5)s cancel out? I figured you'd be left with x^29 and take the square root of the nine to end up with x^2(x+3)(x3).

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0U can't just drop it, I took it out..

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0x^2(x5) 9(x5)=(x5)[x^29] = (x5)(x3)(x+3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So one of the x5s goes away, then? And you're left with (x5)(x3)(x+3) < that bit?

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0yes and the x5 doesnt go away anywhere, I just take it outside of big parenthesis, just like you would do: 3x3y = 3(xy), see the same term comes out, x^2(x5) 9(x5) = (x5)(x^2 * 1  9 * 1)

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0x^2(x5) 9(x5) = (x5)(x^2 * 1  9 * 1) = (x5)(x^29)
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